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## Homework Statement

Find the interval of convergence of the power series ∑(x-2)

^{n}/ 3

^{n}

## Homework Equations

ρ

_{n}= |a

_{n+1}| / |a

_{n}|

## The Attempt at a Solution

I got that ρ

_{n}= | (x-2) / 3 |. I set my ρ

_{n}≤ 1, since this is when the series would be convergent. Manipulating that expression, I got that the interval of convergence is -5 ≤ x ≤ 5. The answer in the back of the book is -1 ≤ x ≤ 5. I am confused where the -1 comes from.