Radius of convergence of the power series (2x)^n/n

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SUMMARY

The radius of convergence for the power series \(\frac{(2x)^n}{n}\) is determined using the ratio test, which simplifies to \(\frac{2^n |x|^n}{n}\). The limit as \(n\) approaches infinity reveals that the series converges when \(|x| < \frac{1}{2}\). Therefore, the radius of convergence \(R\) is definitively \(R = \frac{1}{2}\).

PREREQUISITES
  • Understanding of power series and their convergence
  • Familiarity with the ratio test for convergence
  • Basic knowledge of limits in calculus
  • Ability to manipulate algebraic expressions involving exponents
NEXT STEPS
  • Study the ratio test in detail, focusing on absolute values in limits
  • Explore examples of power series with different radii of convergence
  • Learn about other convergence tests, such as the root test
  • Investigate the implications of convergence on function behavior
USEFUL FOR

Students studying calculus, particularly those focusing on series and convergence, as well as educators teaching these concepts in mathematics courses.

isukatphysics69
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Homework Statement


in title

Homework Equations

The Attempt at a Solution


so i know that i have to use the ratio test but i just got completely stuck

((2x)n+1/(n+1)) / ((2x)n) / n )
((2x)n+1 * n) / ((2x)n) * ( n+1) )
((2x)n*(n)) / ((2x)1) * (n+1) )
now i take the limit at inf? i am stuck here i know i need to find x and do an inequality
 
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i made a mistake i see above, i think i have it now 1/2
 
isukatphysics69 said:

Homework Statement


in title
Please put the problem statement here, not in the thread title.
isukatphysics69 said:

Homework Equations

The Attempt at a Solution


so i know that i have to use the ratio test but i just got completely stuck

((2x)n+1/(n+1)) / ((2x)n) / n )
((2x)n+1 * n) / ((2x)n) * ( n+1) )
((2x)n*(n)) / ((2x)1) * (n+1) )
You have a mistake in the line above.
##\frac{(2x)^{n + 1}}{(2x)^n}## simplifies to 2x.

Also, in the ratio test you need to account for the fact that x can be negative. If you look at the description of this test in your textbook, you'll see that the limit is of the absolute values.
##\lim_{n \to \infty}\frac{|a_{n+1}|}{|a_n|}##

For your problem ##|a_n| = |\frac{(2x)^n} n|## which can be simplified to ##\frac{2^n} n |x|^n##
isukatphysics69 said:
now i take the limit at inf? i am stuck here i know i need to find x and do an inequality
isukatphysics69 said:
i made a mistake i see above, i think i have it now 1/2
Yes, R = 1/2
 

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