(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The cornea, a boundary between the air and the aqueous humor, has a 3.0cm focal length when acting alone.

What is its radius of curvature?

2. Relevant equations

n(1)/s + n(2)/s' = (n(2)-n(1))/R

where, n is the index of refraction (unitless), s' is the img dist (cm). and s is the obj. dist (cm). R is the radius (cm).

also, 1/s + 1/s' = 1/f

where, f is the focal length.

also, n(1) is air having a index of refraction of 1.00

and n(2) is the aqueous humor having a index of refraction of 1.34

3. The attempt at a solution

So, I assumed since only f was given as 3.0cm that 1/s' + 1/s could be 1/6.0cm + 1/6.0cm = 1/3.0cm. Then that would give 1.00/6.0cm + 1.34/6.0cm = (1.34-1.00)/R giving R to be 0.87cm but it says that is wrong. Any ideas??? Also, I thought there was a equation editor for this website? I can't seem to see it... Is it only for the premium members?

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# Radius of curvature of the cornea

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