Radius of Curvature to Correct Myopia

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Homework Help Overview

The problem involves correcting myopia through the design of a contact lens, focusing on the relationship between the curvature of the lens surfaces and the refractive indices involved. The original poster presents a scenario where the near point of vision needs to be adjusted from 7 cm to the normal distance of 25 cm.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the required radius of curvature for the contact lens using the Gaussian thin lens equation and related formulas. Some participants question the appropriateness of the approach and suggest alternative methods for deriving the necessary equations.

Discussion Status

Participants are actively engaging with the problem, exploring different equations and concepts related to lens optics. There is a recognition of potential conceptual issues in the original approach, with suggestions for alternative methods being discussed. No consensus has been reached yet.

Contextual Notes

Participants note the assumption of negligible distance between the lens surfaces and air, as well as the need to apply specific formulas for refraction at spherical surfaces. The discussion reflects uncertainty regarding the correct application of these principles.

TeslaCoil137
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Homework Statement


A person's eye has a near point of 7 cm. The cornea at the outer surface of the eye has a refractive index of n_c = 1.376 and forms a convex shape with a radius of curvature of R_2 = 8 mm against air. The figure below shows the same eye with a contact lens (refractive index of n_L = 1.5) mounted against the cornea such that second (right) surface matches the curvature of the cornea (i.e. R_2= 8 mm). Determine the radius R_1 of the first surface of the contact lens that will correct the near point to the normal 25 cm distance from the eye. Assume paraxial and thin lens conditions.
4ee58a0d67.png

Homework Equations


(1) 1/f =1/f_1 + 1/f_2, (2) 1/f_1 = (n/c -1) (1/R_1 -1/R_2), (3) 1/f_2 = (n_L -1)(1/R_2), (4) 1/u + 1/v = 1/f

The Attempt at a Solution


The focal length of the combined lenses required to correct the present myopia is found from the Gaussian thin lens equation as 1/-7 + 1/-25 = 1/f ⇒ f= -5.47. Using paraxial optics and Fermat's principle of least time relevant equations (1)-(3) are easily found by requiring that all paths through the lens take equal time to reach the focus. Substituting (2) and (3) into (1) with the given numbers we find R_1 =-17.98 cm.
 
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The object distance is real +25 cm, but I do not think this is the correct approach.

The applicable formula that I could find is

n/a + n''/b' = (n'-n)/r + (n''-n')/r'

where the object distance for the first surface of the contact lens (curvature radius r) being a, and the final image being formed at b' by the second surface (curvature radius r') and the refractive indices n (air), n' (contact lens), and n'' (fluid)

This was derived from the formula for refraction at a single spherical surface

n/a + n'/b = (n'-n)/r

being applied at both surfaces and assuming that the distance between the two surfaces is negligible

Maybe you are suppose to derive the 1st formula?
 
Ok, thank you. So what's the conceptual issue I have that lead to my approach?
 
Well, for one (4), Gauss's equation for thin lenses, assume that the lens is in air.

What you can also do it apply the second equation in my previous post at both surfaces if you do not have the first one in you handbook and then assume that the distance between the two surfaces are negligible.
 

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