Raising Complex Numbers to Powers of Angles - What Happens?

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SUMMARY

Raising a complex number to the power of an angle in radians involves the use of Euler's formula. Specifically, for the complex number \(i\), the expression \((i)^a\) can be represented as \(e^{(a \cdot \log(i))}\), where \(\log(i) = i \cdot \frac{\pi}{2}\). This results in \((i)^a = e^{(i \cdot a \cdot \pi)}\), yielding a complex number that varies based on the angle \(a\). The discussion highlights the complexity of raising real numbers to angles compared to complex numbers.

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  • Familiarity with Euler's formula and its applications
  • Knowledge of logarithmic functions in the context of complex analysis
  • Basic trigonometry, particularly in relation to angles in radians
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  • Study Euler's formula in depth, focusing on its implications for complex exponentiation
  • Explore the properties of logarithms in complex analysis, particularly \(\log(z)\)
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Andrea2
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is there anyone who can tell me what happen when i raise a complex number to the power of an angle in rad? for example, what is the result of (i)^1rad?
 
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is there anyone who can tell me what happen when i raise a complex number to the power of an angle in rad? for example, what is the result of (i)^1rad?
Since you ask about the power of a COMPLEX number, so I suppose that you already know what happen when you raise a REAL number to the power of an angle in rad. For example, what is the result of 2^1rad ?
 
i don't know exactly what happen if i raise a real number to the power of an angle, i tried to answer also to this question, but five minutes ago i think I've found the answer to my first question, and i think that this problem is more difficult with real numbers than with complex! My solution is that (i)^a = e^(a x log(i)) with a=angle in rad. log(i) = i x p/2 (p=3.1416...), so (i)^a = e^(i x ap), that is a complex number...
 

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