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The question is probably more about different levels of humidity and possible mold.DaveC426913 said:Do I need to put an insulating barrier between my pressure-treated woods and my natural woods to prevent galvanic corrosion?![]()
The question is probably more about different levels of humidity and possible mold.DaveC426913 said:Do I need to put an insulating barrier between my pressure-treated woods and my natural woods to prevent galvanic corrosion?![]()
I've found to deal differently at different times when I use the same word.fresh_42 said:I hate English. Autocorrect wants me to write webserver as web server, but if I apply it to web sites, it insists on one word, <grrrr>. Why is vector space two words and eigenspace only one?
And what is it with the hyphenation? Are there rules, or is it an on-the-spot decision?
Isn't that because website is a word and webserver is not?fresh_42 said:I hate English. Autocorrect wants me to write webserver as web server, but if I apply it to web sites, it insists on one word, <grrrr>. Why is vector space two words and eigenspace only one?
And what is it with the hyphenation? Are there rules, or is it an on-the-spot decision?
Gauss you have to be Cauchy?WWGD said:Vector Calculus _ Stokes_ my curiosity.
Did you include Malliavin Differential in your pantheon of derivatives? Or Frechet?fresh_42 said:Gauss you have to be Cauchy?
Maybe I could do some myself into an insight. Though ito is more of an actual net infinitesimal change and not a rate of change as a derivative.fresh_42 said:Fréchet and Gateaux in Part 2, and material in Part 4, also known as
Euler operator
advective derivative
convective derivative
derivative following the motion
hydrodynamic derivative
Lagrangian derivative
substantial derivative
substantive derivative
Stokes derivative
total derivative
Source: https://www.physicsforums.com/insights/pantheon-derivatives-part-iv/#A-–-Material-Derivative
but I avoided stochastics.
I think we could need quite a few insights from stochastic, and statistics in general. I have observed that they are a very frequent topic on MSE, and we are not specifically good at it, maybe with the exception of @Dale. (I only had a B-C in my exam on a Rosenmontag.)WWGD said:sMaybe I could do some myself into an insight. Though ito is more of an actual net infinitesimal change and not a rate of change as a derivative.
Anyone heard of those new super-fast chargers? Supposedly take just 10-15 minutes for a full charge 0-100%.BillTre said:
After teaching/tutoring GMAT and similar tests, I decided to tell my students that the ratio of area of an equilateral triangle to a circle it's inscribed in is ## \frac{\sqrt 3 \pi}{9}##, and the converse , of an equilateral triangle inscribed in a circle is ##\frac{3\sqrt{3}}{4\pi}##. Just got tired of solving the problem so many times.WWGD said:Another win in my quartel against ETS: the ratio of the area of a circle inscribed in an equilateral triangle is fixed. Thus knowing the radius of the circle is enough to know that of the inscribing triangle.
I'm just wondering why you don't show it in a form that makes it directly clear that the ratio of the larger triangle to the smaller one is 4, for example by making the first one ##\frac{\pi}{3\sqrt{3}}##.WWGD said:After teaching/tutoring GMAT and similar tests, I decided to tell my students that the ratio of area of an equilateral triangle to a circle it's inscribed in is ## \frac{\sqrt 3 \pi}{9}##, and the converse , of an equilateral triangle inscribed in a circle is ##\frac{3\sqrt{3}}{4\pi}##. Just got tired of solving the problem so many times.
The ratio between the two isJonathan Scott said:I'm just wondering why you don't show it in a form that makes it directly clear that the ratio of the larger triangle to the smaller one is 4, for example by making the first one ##\frac{\pi}{3\sqrt{3}}##.
I mean that if you have an equilateral triangle inside a circle inside a triangle, the larger triangle is four times the area of the smaller one, and that is clear from the ratios if you rewrite ##\frac{\sqrt{3}\pi}{9}## as ##\frac{\pi}{3\sqrt{3}}## for consistency with the other ratio. The smaller triangle in terms of the larger one is then simply as follows: $$\frac{\pi}{3\sqrt{3}} \cdot \frac{3\sqrt{3}}{4\pi} = \frac{1}{4}$$WWGD said:The ratio between the two is
##\frac{4\pi^2}{27}##~##1.46##.
Literally a not very cool part of Summer.Ibix said:Ah, British trains. In the last fifteen minutes we have advanced less than one mile. And the air conditioning is broken.
Edit: oh, and although we're at a station they can't open the doors so we can get some fresh air because the (alleged) express is longer than the platform at this tiny stop and they can't only open some doors and if they open all of them some idiot will step out without looking to see if there's a platform and then sue.