Rate Law for A+B Reaction: k[A][B]^2

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SUMMARY

The rate law for the reaction 2A + 3B → products is definitively expressed as rate = k[A][B]^2. This conclusion arises from the definitions of reaction orders: "first order in A" indicates the rate is proportional to the concentration of A, while "second order in B" indicates the rate is proportional to the square of the concentration of B. Therefore, the correct formulation combines these orders to yield the specified rate law.

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) If the rate law for the reaction
2A + 3B → products
is first order in A and second order in B, then the rate law is rate

I initially thought the answer would be k[A]^2 but it's wrong, the correct answer is
k[A]^2
Could anyone explain?? Please, thank you!
 
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"first order in A" means "Proportional to [A]"

"Second order in B" means "Proportional to 2."

Put those together and what do you get?
 

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