Rate of Reaction with Respect to Temperature

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SUMMARY

The discussion focuses on calculating the activation energy of a chemical reaction, given that the reaction rate at 100˚C is four times that at 50˚C. The relevant equation used is the Arrhenius equation, k = e^(-Ea/RT). The activation energy options presented include 1152 kJ/mol, 80.1 kJ/mol, 54.0 kJ/mol, and 27.8 kJ/mol. A participant initially struggled with calculations but later identified a calculation error in their approach.

PREREQUISITES
  • Understanding of the Arrhenius equation and its components
  • Basic knowledge of reaction rates and temperature effects
  • Familiarity with the concept of activation energy
  • Proficiency in algebraic manipulation for solving equations
NEXT STEPS
  • Study the Arrhenius equation in detail, focusing on its application in chemical kinetics
  • Learn about temperature dependence of reaction rates and the concept of the rate constant
  • Explore methods for experimentally determining activation energy
  • Investigate the implications of activation energy on reaction mechanisms
USEFUL FOR

Chemistry students, educators, and professionals involved in chemical kinetics and reaction mechanism studies will benefit from this discussion.

Teemo
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Homework Statement


The rate of a reaction at 100˚C is four times the rate at
50˚C. What is its activation energy?
(A) 1152 kJ. mol-1
(B) 80.1 kJ. mol-1
(C) 54.0 kJ. mol-1
(D) 27.8 kJ. mol-1


Homework Equations


k=e-Ea/RT


The Attempt at a Solution


I plugged in the activation energies into the equation to see the changes in rate at different temperatures, but I can't solve for the one that is 4x the rate at 100 degrees.
 
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Teemo said:
I plugged in the activation energies into the equation to see the changes in rate at different temperatures, but I can't solve for the one that is 4x the rate at 100 degrees.
Please show your work.
 
Nevermind, I had a calculation error :p
 

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