Rather easy problem involving set multiplication

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SUMMARY

The discussion revolves around the mathematical operation of set multiplication, specifically the Cartesian product of a set A = {1, 1, 2, 5} and an interval B = [1, 2]. It is clarified that the set A can be simplified to {1, 2, 5} due to the properties of sets, which do not account for duplicate elements. The product A x B is interpreted through examples, demonstrating how to express the result using set builder notation. The confusion regarding cardinality is addressed, confirming that both sets indeed have different cardinalities, with A having 3 unique elements.

PREREQUISITES
  • Understanding of set theory, particularly the properties of sets and cardinality.
  • Familiarity with Cartesian products and set multiplication.
  • Basic knowledge of interval notation and set builder notation.
  • Experience with mathematical notation and expressions.
NEXT STEPS
  • Study the properties of sets, focusing on cardinality and uniqueness of elements.
  • Learn about Cartesian products in detail, including examples with both sets and intervals.
  • Explore set builder notation and its applications in expressing set operations.
  • Review foundational concepts in set theory to understand unions and intersections.
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Students studying set theory, educators teaching mathematics, and anyone looking to deepen their understanding of set operations and Cartesian products.

U.Renko
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Homework Statement


A = { 1, 1, 2, 5}
B = [1, 2]

find A x B

Homework Equations


not much

The Attempt at a Solution



well, the problem itself seems easy enough
The thing is, I'm not very sure what it means to multiply a set by an interval...

just need a little help with this detail
 
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But what's confusing is that the set {1,1,2,5} is the same as {1,2,5}, by basic set properties.

One way of understanding the product of a set by an interval is by considering a subset
of the product of 2 intervals, say , the interval [1,5], and [1,2] , then {1,2,5}x [1,2] will
just give you three discrete copies of the interval [1,2]. Or look at the square [0,1]x[0,1] , then {0,1}x[0,1] are just the bottom and the top of the square, respectively.
 
You could express the result using set builder notation.

For example:

{1,3}×[0,1] = {(1,y)|0≤y≤1} ∪ {(3,y)|0≤y≤1}

= {(x,y)|x∊{1,3}, 0≤y≤1}
 
SammyS said:
You could express the result using set builder notation.

For example:

{1,3}×[0,1] = {(1,y)|0≤y≤1} ∪ {(3,y)|0≤y≤1}

= {(x,y)|x∊{1,3}, 0≤y≤1}


The thing is, in the book I'm using, up to this exercise, Unions and the such were not defined yet.

also I'm not 100% sure that {1,1,2,5} = {1,2,5}
shouldn't one have cardinality 4 and the other cardinality 3 ?

might make some difference.
 
List the elements in each set. {1,1,2,5} ; {1,2,5} .
 

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