Bashyboy Messages 1,419 Reaction score 5 Thread starter Oct 12, 2012 #1 Homework Statement I attached a file that includes the author's solution, and some of my work. Homework Equations The Attempt at a Solution Attachments problemjpg.jpg 33.4 KB · Views: 1,101
Homework Statement I attached a file that includes the author's solution, and some of my work. Homework Equations The Attempt at a Solution
Mark44 Mentor Insights Author Messages 38,140 Reaction score 10,730 Oct 12, 2012 #2 Bashyboy said: Homework Statement I attached a file that includes the author's solution, and some of my work. Homework Equations The Attempt at a Solution The denominator in the series is not (2n + 1)! It is the product of the odd integers from 1 to 2n + 1.
Bashyboy said: Homework Statement I attached a file that includes the author's solution, and some of my work. Homework Equations The Attempt at a Solution The denominator in the series is not (2n + 1)! It is the product of the odd integers from 1 to 2n + 1.
Mark44 Mentor Insights Author Messages 38,140 Reaction score 10,730 Oct 12, 2012 #4 No, not at all. (2n + 1)! = 1 * 2 * 3 * ... * (2n - 1) * (2n) * (2n + 1) Your expression skips all the even integers. A simple example is 5! vs. 1 * 3 * 5. Clearly they aren't equal.
No, not at all. (2n + 1)! = 1 * 2 * 3 * ... * (2n - 1) * (2n) * (2n + 1) Your expression skips all the even integers. A simple example is 5! vs. 1 * 3 * 5. Clearly they aren't equal.