Rational ratio of frequencies leads to isolating integral of motion

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SUMMARY

The discussion centers on the dynamics of a two-dimensional harmonic oscillator and the implications of the ratio of frequencies, specifically when it is rational. When the ratio \(\frac{\omega_{x}}{\omega_{y}}\) is rational, an additional isolating integral of motion, denoted as \(c\), emerges, allowing the motion to be confined to a closed one-dimensional curve on the surface of a two torus. This contrasts with irrational ratios, where the motion fills the entire surface due to the lack of periodicity. The key takeaway is that rational frequency ratios lead to a reduction in the dimensionality of phase space from four to one.

PREREQUISITES
  • Understanding of two-dimensional harmonic oscillators
  • Familiarity with integrals of motion in classical mechanics
  • Knowledge of phase space concepts
  • Basic grasp of trigonometric functions, particularly \(\cos^{-1}\)
NEXT STEPS
  • Study the implications of rational vs. irrational frequency ratios in dynamical systems
  • Explore the concept of isolating integrals of motion in classical mechanics
  • Learn about the geometry of phase space in relation to toroidal systems
  • Investigate the nth root of unity in complex analysis and its applications in physics
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This discussion is beneficial for physicists, mathematicians, and students studying classical mechanics, particularly those interested in dynamical systems and the behavior of harmonic oscillators.

victorvmotti
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Hello All,

Padmanabhan's discussion of dynamics mentions that in general the two dimensional harmonic oscillator fills the surface of a two torus.

He further notes that there will be an extra isolating integral of motion provided that the ratio of frequencies is a rational number.

[itex]-\frac{\omega_{x}}{\omega_{y}}\cos^{-1}\left(\frac{y}{B}\right)+\cos^{-1}\left(\frac{x}{A}\right)=c[/itex]


This quantity [itex]c[/itex] is clearly another integral of motion. But- in general - this does not isolate the region where the motion takes place any further, because [itex]\cos^{-1}z[/itex] is a multiple-valued function. To see this more clearly, let us write

[itex]x=Acos\left\{c+\frac{\omega_{x}}{\omega_{y}}\Big[Cos^{-1}\left(\frac{y}{B}\right)+2\pi n \Big]\right\}[/itex]

Where [itex]Cos^{-1}z[/itex] (with an uppercase C) denotes the principal value. For a given value of [itex]y[/itex] we will get an infinite number of [itex]x[/itex]'s as we take [itex]n=0, \pm 1, \pm 2, \dots[/itex]

Thus, in general, the curve will fill a region in the [itex](x,y)[/itex] plane.

A special situation arises if [itex](\omega_{x}/\omega_{y})[/itex] is a rational number. In that case, the curve closes on itself after a finite number of cycles. Then [itex]c[/itex] is also an isolating integral and we have three isolating integrals: [itex](E_{x}, E_{y}, c)[/itex]. The motion is confined to closed (one-dimensional) curve on the surface of the torus.

This last part is not still clear to me.

Can someone please explain why a rational ratio of frequencies make a candidate integral of motion single valued and therefore the motion takes place on a closed (one dimensional) curve on the surface of the two torus?
 
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Thanks that you care about this question.

Well I got the answer later from another source.

My confusion was that in the case of a rational ratio, even though periodic, we have still multiple (finitely) values and not a single valued variable.

Turns out that like the nth root of unity in complex plane we can define a single valued function over a multiple (finitely) valued variable. And therefore in the case of a rational ratio we have a new isolating integral of motion which limits the dimension of phase space to just one instead of four.

Clearly in the case of the irrational ration you cannot have a periodic valued variable and therefore the phase space dynamic covers the whole surface of the two torus.
 

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