Raw moments of Gaussian Distribution

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SUMMARY

The discussion focuses on calculating the moments of a Gaussian Distribution, specifically the eighth moment. The user references the first four moments derived from the Gaussian distribution formula U ~ N(μ, σ²), including E[U²], E[U³], and E[U⁴]. It is established that all central moments above the second are zero, simplifying the calculation process. The user provides a detailed method for calculating the third moment, m₃, which is expressed as m₃ = μσ² + μ³.

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SeriousNoob
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I'm wondering if there was a table of moments for a Gaussian Distribution, I found one up to the fourth moment
U \sim N(\mu, \sigma^2)
E[U^2]=\mu^2+\sigma^2
E[U^3]=\mu^3+3\mu\sigma^2
E[U^4]=\mu^4+6\mu\sigma^2+3\sigma^4

I'm doing a problem right now and i need the 8th moment.
 
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It is a straightforward (tedious) integral.
 
You do not need to do integrals if you know the property of the Gaussian distribution that all central moments above 2 are 0. But I'm not saying it is the easiest method. Here is how you do it for m_3:

m_3 = \left< (x-<x>)^2 \right> = <x^3> - 3<x>^3 + 3<x><x^2> + <x>^3 = <x^3> + <x>^3 + 3 <x> ( <x^2> - <x>^2) = m_3 + \mu^3 + 3<x>\sigma^2 = 0

From this we get:

m_3 = \mu \sigma^2 + \mu^3

And so on...
 
Last edited:

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