Ray Tracing for Convex Lens: How to Determine Image Distance and Realness

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The discussion centers on determining the image distance and nature of the image produced by a convex lens using the lens equation. The image is identified as real because it forms on the opposite side of the lens from the light source. The calculations using the lens equation yield an image distance of 6 cm. Participants confirm the accuracy of ray tracing techniques, which illustrate how light rays behave when passing through the lens. Overall, the conversation enhances understanding of lens behavior and reinforces confidence in solving similar problems.
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Homework Statement

lensquestion.png
[/B]
B) Is the image real or virtual? Explain.
C) Using the lens equation, find the image distance.

2. Homework Equations

1/di + 1/do = 1/f

The Attempt at a Solution


A)
lens.png

B) The image is real because it is on the opposite side of the lens as the source of light.

C) do = 6cm f = 3cm
1/do + 1/di = 1/f
1/di = 1/f - 1/do
1/di = do/f(do) - f/f(do)
1/di = (do-f)/(f*do)
di = (f*do)/(do-f) = (3cm * 6cm)/(6cm - 3cm) = (18cm^2)/(3cm) = 6cm
di = 6cm
 
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not too confident about my ray tracing. this is what it shows in the book but i know it differs depending on the situation
 
toothpaste666 said:
not too confident about my ray tracing. this is what it shows in the book but i know it differs depending on the situation
Your ray tracing is all right. The ray entering parallel with the axis goes through the focus on the other side of the lens.
The ray entering through the focus, goes parallel with the axis on the other side.
 
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ok i feel a little more confident that i got both of these problems right. thanks for the help
 
you are welcome.:)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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