Rc circuit multiple choice don't understand why this is the correct answer

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Homework Help Overview

The discussion revolves around an RC circuit problem from a physics exam, specifically focusing on the behavior of the circuit at different time intervals and the implications of short circuits and open circuits on current flow.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the application of loop and junction rules, questioning the increase in variables encountered. There is confusion regarding the treatment of the capacitor using Ohm's law and the implications of its charging behavior over time. Some participants seek clarification on the concept of a short circuit and its recognition in circuit analysis.

Discussion Status

Participants are actively engaging with the concepts, with some expressing understanding of the answer while others seek further clarification on short circuits. Guidance has been provided regarding the nature of short circuits and their role in circuit behavior, but there is no explicit consensus on all aspects of the problem.

Contextual Notes

There is a mention of a specific physics textbook that does not cover the concept of short circuits, which may contribute to the confusion among participants. Additionally, the problem context includes a reference to an exam paper, suggesting constraints on the information available for discussion.

madah12
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Homework Statement


http://physics.ku.edu.kw/LectureNotes/TheoryCourses/PHYS102/ExamPapers/y0910-2-md2.pdf
page 6 number
5

Homework Equations





The Attempt at a Solution


I don't understand how they got the answers ? i applied the loop and junction rule but they only give me more variables to work with
but shouldn't I after a long time be zero? i mean the only answer i can think of is infinity...
 
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I thought of trying to use ohms law as emf=I(total resistance) but the problem is i don't know how to treat the capacitor
also by loop rule i know that whatever change of voltage occurred in the capacitor it is the same as I through the resistance *3R) but still all of that is useless
 
At time t=0 the capacitor "looks like" a short circuit. So what is the expression for the current Io?

After a long time, the capacitor will have charged up to its final value and will "look like" an open circuit (no further current will flow through it). So what's the expression for the current then?
 
I don't know what is a short circuit i know that when the capacitor is full it will be I=e/5R because there is no current in the capacitor , cna you teach me what is a short circuit? it isn't in the book
unviersity physics by young and freedman
 
A short circuit implies a zero ohm (or at least very low resistance) path, often bypassing current around other components. In your circuit, when the switch is first closed and the capacitor is initially uncharged, it "looks like" a zero ohm path for the current -- it "shorts" the 3R resistance so no current will flow through it, all of the current going through the capacitor instead.
 
how can I recognize a short circuit? btw now i see why the answer if 5/2 but i now want to learn how to recognize a short circuit
 
As I stated, a short circuit is a zero resistance path between nodes.

Any unbroken length of wire is a short circuit between its end points. In a DC circuit an uncharged capacitor is initially a short circuit, eventually an open circuit, while an inductor is initially an open circuit and eventually a short circuit.
 
You use short circuits and open circuits to look at what would happen to some parts of a curcuit. You normaly see this when you study thevenin's theorem, kirchhoff's laws etc.
 

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