Uplakshya
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- Homework Statement
- Circuit Description:
• A battery of emf is connected in series with:
– an uncharged capacitor of capacitance 2C
– a second capacitor of capacitance , C which is already charged to CE (its left plate is negative, right plate positive)
– a resistor of resistance .
The order (clockwise) is:
Battery (+ terminal) → Capacitor 2C → Capacitor C (left plate negative, right plate positive) → Resistor R → Battery (– terminal)
Initial Conditions (at )
1. Capacitor C has voltage E, charge .CE
Negative charge on left plate
3. No current has yet flown through the resistor.
Task:
1. Write the correct Kirchhoff-voltage equation around the loop, carefully assigning signs to each term.
2. Derive the differential equation relating (the charge that flows into the capacitor) and .
3. Solve for and explicitly, applying the proper initial condition.
Im an 12 student so use understandable language
"My overall priority is that to find a trick a logical one to generalise this question and find time equation without integration or differentiation". But the trip should be logical and that can be explained"
- Relevant Equations
- KVL
E -q/(2C) + (CE - q)/C -iR = 0
My solution