thanks!kuruman said:One of the equations is for a charging capacitor and the other for a discharging capacitor. To figure out which is which, evaluate each expression at t = 0 and at t → ∞ .
It is not a log; it is a negative exponential.ace8888 said:One has a 1 - the natural log
haruspex said:It is not a log; it is a negative exponential.
Do you understand what these two curves look like?
A capacitor voltage equation is a mathematical formula used to calculate the voltage across a capacitor in a circuit. It takes into account the capacitance of the capacitor, the current flowing through the circuit, and the time it has been charging or discharging.
A capacitor voltage equation is derived from the fundamental principles of electric circuits and the behavior of capacitors. It is based on the relationship between charge, voltage, and capacitance, as well as the rate of change of voltage over time.
The voltage across a capacitor is affected by its capacitance, the amount of charge stored on the plates, the current flowing through the circuit, and the time elapsed since the capacitor was charged or discharged. Additionally, the type and quality of the dielectric material between the plates can also affect the voltage.
The capacitor voltage equation is used in various practical applications, such as in electronic circuits, power supplies, and energy storage systems. It allows engineers to design and analyze circuits that use capacitors, and to predict the behavior of the voltage over time.
Like any mathematical model, the capacitor voltage equation has its limitations. It assumes ideal conditions, such as a constant current and perfect dielectric material, which may not always be the case in real-world scenarios. Additionally, the equation may become less accurate when dealing with high frequencies or high voltages.