1. The problem statement, all variables and given/known data There is an RC circuit with a 6 V battery, a 100 Ohm resistor, and 2.0 microFarad capacitor. At time t = 0, the switch is closed. While this happens, an ammeter measures the current through the resistor. At t = 0.000139 s the ammeter finds that 0.030 A is flowing through the resistor. a) At this instant in time (t = 0.139 milliseconds) what is the charge on the capacitor? 2. Relevant equations V(T) = E (1-e^(-t/RC)) Q(t) = CE(1-e^-t/RC) 3. The attempt at a solution I solved the equation for t = 0.139, but I was wondering whether or not the stuff about the ammeter measuring the current matters? I mean, if so, then I = 0.030 A and I = R/V and Q = CV, so I could also find the charge that way, but when I do that, I get two different answers. What do you suggest? Thanks in advance!