Re-arranging cosh to make x the subject

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SUMMARY

The discussion focuses on rearranging the hyperbolic cosine function to solve for x in the equation y = 38cosh(x/40) when y = 50. The key takeaway is that to isolate x, one must utilize the inverse hyperbolic cosine function, arccosh. Specifically, the solution involves first dividing both sides by 38, resulting in cosh(x/40) = 50/38. Subsequently, applying the arccosh function yields x = 40 * arccosh(50/38).

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zfleas
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Hi everyone, my first post so forgive me if its rubbish!
I have been set a question in my HNC course and have hit a wall with where to proceed with it. I would just post the question but rather than that and you giving me the answer I would rather learn how to do it myself, so I will answer a similar one.

I need to calculate x in the following when y = 50
y=38cosh(x/40)

How would I go about making x the subject so I can calculate it? Or is it even more simple than that?
Any help is greatly appreciated
Cheers
:)
 
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There is a defined function for this, arccosh.
 

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