Re: Axis Transformation, time -> distance

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SUMMARY

The discussion centers on transforming a graph from Force vs. Time to Force vs. Distance using the equation distance = 1/2(F/mass)*(t^2). Mike seeks confirmation on this method. However, it is established that this approach is valid only under the assumption of constant force. The relationship between distance and time is more complex and can be expressed through a double integral involving the force function over time.

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miloko
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Hi all,

I have a graph, plotted as Force vs. Time. Now, I want to plot the graph as Force vs. Distance. I'm taking distance = 1/2(F/mass)*(t^2). I think this is the right way to do it, but just need some confirmation.

Thanks,
Mike
 
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That would work only if the force is constant. Generally, the relation between distance and time is a bit more complicated:

[tex]x-x_0 = v_0 t + \int_{0}^{t}\int_{0}^{t'}\frac {F(t'')}{m}dt'' dt'[/tex]
 

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