- #1
hadi amiri 4
- 98
- 1
Can anyone help me with this [tex]\int \frac{dx}{x^7-x}[/tex]?
Last edited:
I didn't see that one..1/(x^7-x) = 1/(x*(x^6-1))= -1/x+x^5/(x^6-1)
When we talk about "re-writing the denominator," we are referring to changing the expression in the denominator of a fraction to a different form that may be easier to work with. In this case, we are looking at an expression with a denominator of x*(x^6-1)
and we want to re-write it as x*(x^3-1)*(x^3+1)
.
Re-writing the denominator can help us simplify or manipulate a fraction in order to solve a problem or answer a question. In this case, re-writing the denominator as x*(x^3-1)*(x^3+1)
may help us to more easily factor or cancel out terms in the fraction.
In general, there is no set formula for re-writing a denominator. It often involves analyzing the expression and looking for patterns or relationships between the terms. In this case, we can see that the expression x^6-1
can be factored into (x^3-1)*(x^3+1)
, which allows us to re-write the denominator as x*(x^3-1)*(x^3+1)
.
To re-write the denominator in this case, we first need to identify any common factors between the terms. In this example, we can see that both x^6
and 1
can be factored into x^3
and 1
, respectively. Then, we can use the distributive property to factor out the common factor of x^3
, resulting in the expression x*(x^3-1)*(x^3+1)
.
Re-writing the denominator does not change the overall value of the expression, but it may help us to simplify or manipulate it in order to solve a problem or answer a question. In this case, re-writing the denominator as x*(x^3-1)*(x^3+1)
allows us to factor or cancel out terms in the fraction, which may make it easier to work with.