Reacting Zn with .248M HCl to Produce H2

Thread starter kippy
Start date Sep 3, 2006
Tags

Hcl

Click For Summary

SUMMARY

The discussion focuses on calculating the volume of 0.248 M hydrochloric acid (HCl) required to react with 1.36 grams of zinc (Zn) to produce hydrogen gas (H2). The stoichiometry of the reaction indicates that 1 mole of Zn reacts with 2 moles of HCl. Given the molar mass of zinc is 65.38 g/mol, the calculation reveals that approximately 0.0208 moles of Zn are present, necessitating 0.0416 moles of HCl. This translates to a volume of approximately 168.5 mL of 0.248 M HCl needed for the reaction.

PREREQUISITES

Understanding of stoichiometry and mole calculations
Familiarity with molarity and solution concentration
Knowledge of chemical reaction equations
Basic skills in unit conversion and dimensional analysis

NEXT STEPS

Study stoichiometric calculations in chemical reactions
Learn about molarity and how to prepare solutions
Explore the properties and reactions of zinc with acids
Review gas laws and calculations related to hydrogen production

USEFUL FOR

Chemistry students, educators, and anyone involved in laboratory work or chemical engineering who needs to understand acid-metal reactions and stoichiometric calculations.

Sep 3, 2006

kippy

How many milliters of .248 M HCl are needed to react with 1.36g of zinc to produce hydrogen gas

Chemistry news on Phys.org

Sep 3, 2006

Gokul43201

Staff Emeritus

Science Advisor

Gold Member

If you're stuck, you need to show what you've done till the point that you got stuck. Without that, we can not help in any way. Please read again, the posting guidelines for homework/textbook problems.