Reaction between mgso4 +k2co3?

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Discussion Overview

The discussion revolves around a chemistry question from 1989 regarding the reaction between magnesium sulfate (MgSO4) and potassium carbonate (K2CO3). Participants explore the products of this reaction, including gas evolution and precipitate formation, while seeking clarification on solubility principles related to the involved ions.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant suggests that the gas evolved in the reaction is carbon dioxide (CO2) and identifies calcium carbonate (CaCO3) as one of the precipitates, questioning the other precipitate.
  • Another participant confirms the identification of K2CO3 based on the lilac color indicating potassium and the white precipitate suggesting CO2, proposing that magnesium carbonate (MgCO3) is the precipitate formed from the reaction.
  • A participant questions the reasoning behind the assertion that potassium's high solubility implies that the precipitate must come from magnesium, seeking clarification on the solubility comparison between potassium and magnesium.
  • In response, it is explained that potassium, being in group 1, is more soluble than magnesium, which is in group 2, leading to the conclusion that magnesium would combine with carbonate (CO3) instead of sulfate (SO4).

Areas of Agreement / Disagreement

Participants express varying degrees of certainty about the products of the reaction, with some agreeing on the identification of K2CO3 and MgCO3, while others seek further clarification on the reasoning behind solubility and precipitate formation. The discussion remains unresolved regarding the complete understanding of the reaction products.

Contextual Notes

The discussion includes assumptions about solubility rules and the behavior of ions in solution, which may not be universally applicable without further context. The reasoning behind the identification of precipitates and gases is based on general chemical principles that may require additional validation.

markosheehan
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can someone help me with the 1989 question.

View attachment 7341

i think part i is k2(c03)
for ii the gas given of is co2. 1 one the precipitates given off was caco3. i am not sure what the other was. is it supposed to be a reaction between mgso4 +k2co3?
 

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markosheehan said:
can someone help me with the 1989 question.

i think part i is k2(c03)
for ii the gas given of is co2. 1 one the precipitates given off was caco3. i am not sure what the other was. is it supposed to be a reaction between mgso4 +k2co3?

Hi markosheehan,

Indeed, the lilac color indicates we have K.
And the white precipitate of the colorless gas in lime water suggests CO2.
So X is probably $\ce{K2CO3}$.

And yes, when combining a solution of $\ce{K2CO3}$ with a solution of $\ce{MgSO4}$, we have:
$$\ce{2K+ + CO3^{2-} + Mg^{2+} + SO4^{2-}}$$
Since K is very soluble, the precipitate must be from Mg.
And since we can assume that it won't be the original magnesium sulfate, which was dissolved after all, that leaves us with only one choice.
It should be $\ce{MgCO3}$, which is white, confirming our analysis.
 
thanks for your help

how did you know "Since K is very soluble, the precipitate must be from Mg."

is it just a general rule you just learn off that potassium is more soluble than mg. just because k is more soluble than mg how did you know mg would join with the (co3)^2-

thanks
 
markosheehan said:
thanks for your help

how did you know "Since K is very soluble, the precipitate must be from Mg."

is it just a general rule you just learn off that potassium is more soluble than mg. just because k is more soluble than mg how did you know mg would join with the (co3)^2-

thanks
Potassium is in group 1, meaning it has a single electron in its outer shell that it is eager to release, becoming an ion that is dissolved in water.
This holds true for all metals in group 1 (Li, K, Na).
So we can expect Mg (group 2) to be less soluble than K.
This is a general rule -- chemical intuition if you will.

That means that Mg must join with either CO3 or with SO4.
Since it was already dissolved with SO4, the obvious candidate is CO3.
 
thanks
 

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