Reactions of Halogens with Metals

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SUMMARY

The forum discussion focuses on the reactions of bromine (Br2) and iodine (I2) with copper (Cu) metal, specifically examining the oxidation of copper in aqueous and methanol solutions. The net ionic equations presented are Cu (s) + Br2 (aq) -> Cu2+ (aq) + 2Br- (aq) and Cu (s) + I2 (methanol) -> Cu2+ (methanol) + 2I- (methanol). Participants debate the formation of precipitates, particularly whether CuI or CuBr forms as a solid product, with a consensus that CuI is likely to be a solid while the formation of CuBr versus CuBr2 remains uncertain.

PREREQUISITES
  • Understanding of oxidation-reduction reactions
  • Familiarity with net ionic equations
  • Knowledge of halogen chemistry
  • Basic laboratory techniques for conducting chemical reactions
NEXT STEPS
  • Research the properties of copper halides, specifically CuI and CuBr
  • Study the solubility rules for ionic compounds in aqueous solutions
  • Learn about the oxidation states of halogens in redox reactions
  • Explore laboratory methods for observing color changes in chemical reactions
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Chemistry students, laboratory technicians, and educators interested in redox reactions and halogen chemistry will benefit from this discussion.

tevatron1
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To test the ability of Br2 and I2 to oxidize copper metal, the reactions take place between Br2water and I2 solution with copper:

Cu (s) + Br2 (aq) -> Cu2+ (aq) + 2Br- (Aq)

Cu(s) + I2 (methanol) -> Cu2+ (methanol) + 2I- (methanol).

Write the net ionic equations describing the results of these two experiments.

I believe that the Cu (s) should oxidize, and thus color change. Particularly with Br2 water (bromide water), so I recorded the net ionic equation as 2Cu (s) + Br2 (aq) -> 2CuBr(s)

However, I'm unsure if this is correct or what to do with the second equation.

Has anyone ever done these reactions or know them off hand? Is it possible that a precipiate could form between Cu2+ and I2?
 
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Why not CuI?

Actually I am sure about CuI, but I am not convinced you will get CuBr and not CuBr2.
 
Borek said:
Why not CuI?

Actually I am sure about CuI, but I am not convinced you will get CuBr and not CuBr2.

Well, CuI would have to be a solid. And I'm not convinced a solid was formed in this case. I suppose my main question is if the reaction between Cu and I2 results in a color change to Cu, would the product be a solid? CuI would have to be a solid to be written as such in the net ionic equation.

The lab notes predict Br2 reduces to Br2-, hence my writing CuBr
 

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