Real Analysis: Hardy Littlewood

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SUMMARY

The discussion focuses on establishing the inequality \( f^*(x) \ge \frac{c}{|x| \ln \frac{1}{x}} \) for the function \( f(x) = \frac{1}{|x| (\ln \frac{1}{x})^2} \) when \( |x| \le \frac{1}{2} \) and 0 otherwise. The key equation utilized is \( f^*(x) = \sup_{x \in B} \frac{1}{m(B)} \int_B |f(y)| dy \) for \( x \in \mathbb{R}^d \). The participant overcame initial confusion by working backwards from the solution, ultimately realizing the importance of the integral setup: \( \sup_{x \in B} \frac{1}{m(B)} \int_B \frac{1}{|x| (\ln \frac{1}{x})^2} \ge \frac{1}{2|x|} \int_{-|x|}^{|x|} \frac{1}{|x| (\ln \frac{1}{x})^2} \).

PREREQUISITES
  • Understanding of Hardy-Littlewood inequalities
  • Familiarity with Lebesgue integration
  • Knowledge of supremum and measure theory concepts
  • Proficiency in logarithmic functions and their properties
NEXT STEPS
  • Study the properties of Hardy-Littlewood inequalities in detail
  • Learn about Lebesgue measure and integration techniques
  • Explore advanced topics in functional analysis related to supremum functions
  • Investigate the applications of logarithmic functions in real analysis
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Mathematics students, particularly those studying real analysis, and researchers focusing on functional inequalities and integration techniques will benefit from this discussion.

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Homework Statement


Establish the Inequality ##f^*(x)\ge \frac{c}{|x|ln\frac{1}{x}}## for
##f(x)=\frac{1}{|x|(ln\frac{1}{x})^2}## if ##|x|\le 1/2## and 0 otherwise

Homework Equations


##f^*(x)=\sup_{x\in B} \frac{1}{m(B)} \int_B|f(y)|dy \quad x\in \mathbb{R}^d##

The Attempt at a Solution


Disregard, I figured it out.
 
Last edited:
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What was the sticking point that you overcame?
 
I was stuck on the first step. I was able to work in reverse from the solution but felt like I was missing a key idea doing it that way. Namely,

##\sup_{x\in B} \frac{1}{m(B)} \int_B \frac{1}{|x|(ln\frac{1}{x})^2}\ge \frac{1}{2|x|}\int_{-|x|}^{|x|} \frac{1}{|x|(ln\frac{1}{x})^2}##

from there you just work out the integral.
 
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