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Homework Help: Real Analysis related to Least Upper Bound

  1. Jan 16, 2008 #1
    Give an example of a function f for which [tex]\exists s \epsilon R P(s)[/tex] ^ Q(s) ^ U(s)
    P(s) is [tex]\forall x \epsilon R f(x) >= s[/tex]
    Q(s) is [tex]\forall t \epsilon R ( P(t) => s >= t )[/tex]
    U(s) is [tex]\exists y\epsilon R s.t. \forall x\epsilon R (f(x) = s => x = y)
    [/tex]
    So this was actually a two part question, and this is the second part, the first part involved the function f(x) = sin(x) for which P(s)^Q(s)^U(s) could never be true.
    I am not sure how to approach this, should I just think of random functions? or is there a logical way to do this.

    The only thing I know is what I found from the first part of this question which is
    P(s) defines the lower bound when true
    Q(s) defines the greatest lower bound when true
    U(s) I'm not so sure, I think something along the lines of y exist in reals, so the function must be all values of reals.. but this makes no sense as the function would not be bounded then. so I guess I am wrong.

    Any help would be greatly appreciated.
     
  2. jcsd
  3. Jan 17, 2008 #2
    dear braindead101
    let us consider a function [tex]f[/tex] such that [tex]f(0) =0[/tex] and [tex] f(x) \neq 0 \forall x \in \mathbf{R}\backslash\{0\} [/tex]. Does U(0) hold?
     
  4. Jan 17, 2008 #3
    okay so, f(x) does not equal 0 for all x in reals, and then what does the last part mean? the backslash {0}
     
  5. Jan 17, 2008 #4
    [tex] \mathbf{R} \backslash \{0\} [/tex] is the set R with the element 0 removed. well i will give you an example of what i had in mind.
    consider the function f(x)=x.
    U(x) will hold for all x because f is a bijective map, so the inverse image of each [tex]y \in R [/tex] will consist of a set with one element.
     
  6. Jan 17, 2008 #5
    so f(x) = x but with no 0
    i don't understand how p(x) and q(x) will be satisfied, arn't they not bounded in f(x) = x?
     
  7. Jan 18, 2008 #6
    dear braindead101
    i gave you an example of an function where U(s) holds for all s because you seemed unsure about what the meaning of U(s) is. Of course you are looking after a function which has a unique minimum (so that p(x) and q(x) will be satisfied).
     
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