Real Analysis related to Least Upper Bound

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Homework Help Overview

The discussion revolves around the properties of functions in the context of real analysis, specifically focusing on the least upper bound and related conditions defined by P(s), Q(s), and U(s). The original poster seeks to identify a function that satisfies these conditions after exploring an earlier example involving the sine function.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore various functions to determine if they meet the criteria set by P(s), Q(s), and U(s). Questions arise about the implications of these definitions and the nature of the functions being considered, including the uniqueness of minimum values and the boundedness of functions.

Discussion Status

The conversation is ongoing, with participants providing examples and questioning the definitions of the properties involved. Some guidance has been offered regarding the interpretation of U(s) and the characteristics of functions that might satisfy the conditions, but no consensus has been reached on a specific function that meets all criteria.

Contextual Notes

There is a focus on the definitions of the properties P(s), Q(s), and U(s), with some participants expressing uncertainty about their implications. The discussion also highlights the challenge of finding functions that are both bounded and meet the specified conditions.

braindead101
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Give an example of a function f for which \exists s \epsilon R P(s) ^ Q(s) ^ U(s)
P(s) is \forall x \epsilon R f(x) >= s
Q(s) is \forall t \epsilon R ( P(t) => s >= t )
U(s) is \exists y\epsilon R s.t. \forall x\epsilon R (f(x) = s =&gt; x = y)<br />
So this was actually a two part question, and this is the second part, the first part involved the function f(x) = sin(x) for which P(s)^Q(s)^U(s) could never be true.
I am not sure how to approach this, should I just think of random functions? or is there a logical way to do this.

The only thing I know is what I found from the first part of this question which is
P(s) defines the lower bound when true
Q(s) defines the greatest lower bound when true
U(s) I'm not so sure, I think something along the lines of y exist in reals, so the function must be all values of reals.. but this makes no sense as the function would not be bounded then. so I guess I am wrong.

Any help would be greatly appreciated.
 
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dear braindead101
let us consider a function f such that f(0) =0 and f(x) \neq 0 \forall x \in \mathbf{R}\backslash\{0\}. Does U(0) hold?
 
okay so, f(x) does not equal 0 for all x in reals, and then what does the last part mean? the backslash {0}
 
\mathbf{R} \backslash \{0\} is the set R with the element 0 removed. well i will give you an example of what i had in mind.
consider the function f(x)=x.
U(x) will hold for all x because f is a bijective map, so the inverse image of each y \in R will consist of a set with one element.
 
so f(x) = x but with no 0
i don't understand how p(x) and q(x) will be satisfied, arn't they not bounded in f(x) = x?
 
braindead101 said:
so f(x) = x but with no 0
i don't understand how p(x) and q(x) will be satisfied, arn't they not bounded in f(x) = x?

dear braindead101
i gave you an example of an function where U(s) holds for all s because you seemed unsure about what the meaning of U(s) is. Of course you are looking after a function which has a unique minimum (so that p(x) and q(x) will be satisfied).
 

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