Real integrals with complex coefficients

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SUMMARY

The discussion centers on the validity of applying traditional calculus techniques to integrals with complex coefficients, specifically examining the integral \(\int_{-\infty}^{\infty} e^{-\left(t + i\alpha\right)^2} dt\) where \(\alpha\) is a real number. The user successfully employs u-substitution to transform the integral into a familiar form, concluding that the result is \(\sqrt{\pi}\). The conversation highlights that while complex coefficients introduce new considerations, established calculus methods can still yield valid results under certain conditions. The use of tools like Wolfram Alpha further supports the correctness of the approach.

PREREQUISITES
  • Understanding of complex analysis fundamentals
  • Familiarity with real variable calculus techniques
  • Knowledge of integral transforms, particularly Fourier transforms
  • Experience with mathematical software such as Wolfram Alpha
NEXT STEPS
  • Explore the implications of complex coefficients in integrals
  • Study the properties of Fourier transforms in relation to complex variables
  • Investigate the convergence criteria for integrals involving complex coefficients
  • Learn advanced techniques in complex analysis, such as contour integration
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Mathematicians, physics students, and anyone interested in the intersection of real analysis and complex analysis, particularly those working with integrals involving complex coefficients.

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I'm curious about the validity of various techniques from good old calculus in one real variable when dealing with complex coefficients. I know enough complex analysis to know that the rules change when dealing with complex variables, but I'm curious about the case when the variables are still real and its just coefficients that are complex.

For example, suppose you wanted to do the following integral:

[tex]\int_{-\infty}^{\infty} e^{-\left(t + i\alpha\right)^2} dt[/tex]

with [itex]\alpha[/itex] real. Can I just do u-substitution like this:

[tex]u = t + i\alpha \rightarrow du = dt \\<br /> \int_{-\infty}^{\infty} e^{-\left(t + i\alpha\right)^2} dt =<br /> \int_{u=-\infty}^{u=\infty} e^{-u^2} du[/tex]

and conclude the integral is [itex]\sqrt{\pi}[/itex] like usual? Punching it into Wolfram Alpha confirms that's the result, so it's more whether or not what I did was valid in general that I'm interested in, rather than this particular result. Can I still use the familiar tricks, or does the mere presence of complex numbers invalidate these old techniques?
 
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I am not sure about the validity of the technique but in this case it looks like the right answer. Expand the exponent and get eα2 multiplying the Fourier transform of e-t2, which is e2 (with some constants including √π).
 

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