Really Simple Logarithmic Question

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The discussion focuses on simplifying the function f(n) = log(n)^(log(n)) for Big-O notation. The user attempts to demonstrate that f(n) simplifies to n^(log(log(n))). They apply logarithmic properties, specifically log(a^b) = b*log(a), to derive the relationship. By using base 10 logarithms, they confirm that f(n) can be expressed as (10^(log(n)))^(log(log(n))), ultimately leading to the conclusion that f(n) = n^(log(log(n))). The conversation emphasizes understanding logarithmic transformations in Big-O notation.
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Homework Statement



1. f(n) = log(n) ^ (log(n)). Simplify for Big-O notation.

The Attempt at a Solution


1.

I'm just trying to prove a big-O notation for one of my courses, and this was simplified to

f(n) = n^log(log(n))

And I'm having a hard time seeing why. Any guidance would be appreciated.
 
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\log{f(n)} = \log( (\log n)^{\log{n} } )
Using \log(a^b) = b\log(a)
\log f(n) = \log(n) \log( \log(n))

Let's say the logs are base 10. Then
10^{\log f(n)} = 10^{\log(n) \log(\log(n)}
f(n) = (10^{log(n)})^{\log(\log(n))}
f(n) = n^{log(log(n))}
 

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