Really stuck on an easy questionintegral of 1/(2^x)

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SUMMARY

The integral of 1/(2^x) can be simplified to (1/2)^x, which is equivalent to 2^(-x). To solve the integral, recognize that 2^(-x) can be expressed using the exponential function as e^(-ln(2)x). This transformation allows for straightforward integration using standard techniques. The final result of the integral is -1/(ln(2) * 2^x) + C, where C is the constant of integration.

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Hi there!
I am stuck on how to work out the integral of 1/(2^x) and was hoping someone could guide me step by step to the answer? so confused and would really appreciate the help thanks!
 
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Well
1/2^x=(1/2)^x
what is
((1/2)^x)'
?
 
It might help you to recognize that [itex]1/2^x= 2^{-x}[/itex]. Also, [itex]2^{-x}= e^{ln(2^{-x})}= e^{(-ln(2)x)}[/itex].
 

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