Really stuck on an easy questionintegral of 1/(2^x)

[gnick]

Hi there!
I am stuck on how to work out the integral of 1/(2^x) and was hoping someone could guide me step by step to the answer? so confused and would really appreciate the help thanks!

 

[lurflurf]

Well
1/2^x=(1/2)^x
what is
((1/2)^x)'
?

 

[HallsofIvy]

It might help you to recognize that $1/2^x= 2^{-x}$. Also, $2^{-x}= e^{ln(2^{-x})}= e^{(-ln(2)x)}$.