Rearranging an equation, It includes a square root.

Click For Summary
SUMMARY

The equation sqrt[(r^2)+(110^2)] + r = 160 can be solved to find the value of r. The exact solution is r = 42.1875, derived from rearranging the equation to sqrt(r²+110²) = 160 - r. By squaring both sides and simplifying, the equation reduces to 320r = 160² - 110², leading to the final calculation of r = 13500/320.

PREREQUISITES
  • Understanding of algebraic manipulation
  • Familiarity with square roots and squaring equations
  • Basic knowledge of solving quadratic equations
  • Experience with online equation solvers
NEXT STEPS
  • Study algebraic techniques for rearranging equations
  • Learn about quadratic equations and their solutions
  • Explore the use of online equation solvers for complex problems
  • Practice solving equations involving square roots
USEFUL FOR

Students, educators, and anyone interested in mastering algebraic problem-solving techniques, particularly those involving square roots and quadratic equations.

Georgepowell
Messages
179
Reaction score
0
I want to find the value of r such that:

sqrt[(r^2)+(110^2)] + r = 160

Is there a way of doing it?

I have found a solution through trial and error (1dp). But I want a method of finding an exact answer.

Thanks
 
Mathematics news on Phys.org
I just found the solution:

r = (675/16) using an online equation solver.

But how do I get to that? Without trial and error?
 
Doesn't matter anymore, I figured it out:

sqrt(r²+110²) = 160 -r

r² + 110² = (160 - r)²
r² + 110² = 160² - 2*160*r +r²
320r = 160²-110²
r = 13500/320 = 42.1875
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K