Rearranging simple equation by making x the subject: 205 = ((4*pi*x*f)/c)^2

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Discussion Overview

The discussion revolves around rearranging the equation 205 = ((4*pi*x*f)/c)^2 to isolate x as the subject. Participants explore different methods for manipulating the equation, focusing on algebraic techniques and the steps involved in the rearrangement process.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant presents their initial attempt at rearranging the equation but expresses uncertainty about the evaluation of their result.
  • Another participant provides a rearranged form of the equation, suggesting that x can be expressed as x = ±(sqrt{205} * c) / (4 * pi * f).
  • A third participant elaborates on the process of "backing out" of the expression by taking the square root and performing algebraic operations to isolate x, arriving at the same expression as the previous reply.
  • A later reply expresses gratitude for the clarification and acknowledges the effectiveness of the backward approach in solving the equation.

Areas of Agreement / Disagreement

Participants generally agree on the steps to rearranging the equation, with multiple methods presented. However, there is no explicit consensus on the evaluation of the initial participant's result.

Contextual Notes

The discussion does not address potential limitations or assumptions in the algebraic manipulation, nor does it resolve any uncertainties regarding the initial evaluation of the equation.

Who May Find This Useful

Readers interested in algebraic manipulation, particularly in the context of physics equations, may find this discussion beneficial.

duckau
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Hi,

It's been a while and I'm a bit rusty.. I am attempting to rearrange the following equation to make x the subject:

205 = ((4*pi*x*f)/c)^2I have attempted:

205/x^2 = ((4*pi)^2*f^2) / c^2
x^2/205 = c^2/(4*pi)^2*f^2

then

x^2 = 205 * (c^2/((4*pi)^3)*f^2)
x = \sqrt{205*(c^2/((4*pi)^2)*f^2)}

Unfortunately my answer doesn't evaluate. Any tips on my process?

Thanks!
 
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Hi duckau and welcome to MHB! :D

$$205=\left(\frac{4\pi x f}{c}\right)^2$$

$$\pm\sqrt{205}=\frac{4\pi x f}{c}$$

$$\pm\frac{\sqrt{205}c}{4\pi f}=x$$

Does that help?
 
"Back out" of the expression by "undoing" each thing that was done to x:
We have $\left(\frac{4\pi x f}{c}\right)^2= 205$. Since the last thing done is squaring, the first thing we do is take the square root of each side: $\frac{4\pi x f}{c}= \pm\sqrt{205}$. On the left we are dividing by c so multiply both sides by c: $4\pi x f= \pm c\sqrt{205}$. We now have x multiplied by $4\pi f$ so, finally, divide both sides by $4\pi f$:

$x= \pm \frac{c\sqrt{205}}{4\pi f}$.
 
Thanks a lot.. that's exactly what I was after.

I appreciate the advice regarding working backwards instead of attempting to solve the equation!

Regards.
 

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