Recovering the generator of rotation from canonical commutation relations

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The discussion centers on the relationship between the definition of angular momentum in quantum mechanics and its representation as a generator of infinitesimal rotations. The participant references Sakurai's definition, which connects angular momentum to classical mechanics through commutation relations. They question whether defining angular momentum by its commutation relations is equivalent to defining it as a generator of infinitesimal rotations. The conversation highlights the importance of establishing the Lie group first to derive its generators and subsequently the commutation relations. Ultimately, the discussion emphasizes the interconnectedness of these concepts in advanced quantum mechanics.
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I'm having a course in advanced quantum mechanics, and we're using the book by Sakurai. In his definition of angular momentum he argues from what the classical generator of angular momentum is, and such he defines the generator for infitesimal rotations as

D(\widehat{n},d\phi)=1-i\left(\bold{J}\cdot\widehat{n}/\hbar\right)d\phi

Where J is the angular momentum operator and \widehat{n} is the rotation axis.
In this way he shows that the angular momentum operator J satisfies the canonical commutation relations

[J_i,J_j]=i\hbar \epsilon_{i,j,k}J_k

My question is this:
Is it possible to define the commutation relations as above, and then derive the expression of the generator of infintesimal relations to be the above expression? That is: Is defining angular momentum by it's commutation relations fully equivalent to defining it as a generator of infinitesimal rotations?

I like the definition of angular momentum by it's commutation relations, since you can make a reasonable connection to classical machanics by the rule that the poisson bracket of classical quantities gets replaced by i\hbar times the quantum mechanical commutator of the corresponding operators. For example [x_i,p_j]_{poisson}=\delta_i^j\rightarrow i\hbar[x_i,p_j]_{commutator}=\delta_i^j
 
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I think you must FIRST give the Lie Group, once we have the LIe group can obtain its generators, and from the generators you can get the commutation relation.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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