Red Shift Energy: Understanding the Light Phenomena

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SUMMARY

The discussion centers on the concept of red shift in light phenomena, emphasizing that light should not be viewed merely as a stream of photons but rather as a wave phenomenon. Participants clarify that photons are excitations of the electromagnetic field and that the energy of a photon is proportional to its momentum, which is affected by the relative velocity of the emitter. The conversation references Richard Feynman's insights from quantum electrodynamics (QED), highlighting that QED can explain various light phenomena that classical wave theory cannot.

PREREQUISITES
  • Understanding of electromagnetic wave theory
  • Familiarity with quantum electrodynamics (QED)
  • Knowledge of momentum and energy relationships in physics
  • Basic concepts of photon behavior and interactions
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  • Study the principles of quantum electrodynamics (QED)
  • Explore the relationship between momentum and energy in light
  • Research the implications of red shift in astrophysics
  • Examine the differences between classical wave theory and quantum theories of light
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Physicists, students of quantum mechanics, and anyone interested in advanced concepts of light and electromagnetic theory.

gmalcolm77
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I find it difficult to conceptualize red shift when thinking of light as a stream of photons. In thinking of it as a wave phenomena, I can see it as a matter of a given energy concentration/area. But why should a photon lose energy as a result of the velocity of the emitter?
 
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gmalcolm77 said:
I find it difficult to conceptualize red shift when thinking of light as a stream of photons ...
That's good because light is not a stream of photons. Photons are things you get when an electromagnetic wave interacts with atoms, or to say it another way, photons are excitations of the electromagnetic field
 
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gmalcolm77 said:
I find it difficult to conceptualize red shift when thinking of light as a stream of photons. In thinking of it as a wave phenomena, I can see it as a matter of a given energy concentration/area. But why should a photon lose energy as a result of the velocity of the emitter?
The EM field carries momentum k=λ for a mode with wavelength λ. As with bodies with mass the observed momentum depends on relative velocity and light obeys this so that a different wavelength is observed for different relative velocities.

As @phinds has said you don't need to think of photons - just a field that has momentum but is massless.
 
gmalcolm77 said:
But why should a photon lose energy as a result of the velocity of the emitter?
Because energy of photon is proportional to its momentum, and momentum depends on the velocity of the frame of reference.
 
phinds said:
That's good because light is not a stream of photons.

That's interesting, as Feynman said in QED that "...every phenomenon about light that has been observed in detail can be explained by the theory of quantum electrodynamics." And later he explained that the reverse was not true. That wave theory could not explain some phenomenon that QED could. So what would be the basis for believing that light is not a stream of photon 'particles'? And why wouldn't red shift be explainable by QED?
 
gmalcolm77 said:
That's interesting, as Feynman said in QED that "...every phenomenon about light that has been observed in detail can be explained by the theory of quantum electrodynamics."
Yes, but..
So what would be the basis for believing that light is not a stream of photon 'particles'?
That's not what QED says, at least not if you're understanding "stream of photon particles" to be something like the way that a flowing river is a stream of water molecules. We have many threads that try to explain the relationship between photons and classical electromagnetic radiation - this one would be a good start https://www.physicsforums.com/threads/what-is-a-photon.879128/#post-5522356.
 

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