Reduced Row Echelon/Solution Set Problem

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Homework Help Overview

The discussion revolves around understanding the solution set of linear systems represented in reduced row echelon form. Participants are exploring the implications of the matrix structure on the nature of solutions, particularly in cases of homogeneous systems and systems with varying numbers of equations and unknowns.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the meaning of the solution set for linear systems and how to interpret the reduced row echelon forms. There is discussion about the types of solutions possible (zero, one, or infinite) based on the matrix structure.

Discussion Status

Some participants have provided insights into the nature of solutions based on the matrix form, suggesting that the original poster's matrix indicates an infinite number of solutions due to having more unknowns than equations. Guidance has been offered on introducing parameters to express solutions in terms of those parameters.

Contextual Notes

Participants are working within the constraints of homework rules that require them to describe solution sets without providing complete solutions. There is an emphasis on understanding the implications of the reduced row echelon form rather than directly solving the systems.

iasc
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The question reads "Use the reduced row echelon forms that you computed to describe the solution set for each of two linear systems we consider".

What I don't understand is what it means by The solution set for each of the two linear systems.
Could someone clear this up for me.

Any help appreciated.
Thanks.
 
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After solving a matrix you will have either zero, one, or an infinite number of solutions. For example the solution [tex]x_{1}=0[/tex] [tex]x_2=0[/tex] [tex]x_3=0[/tex] might be the solution set to a homogeneous system. Once you get the matrix to reduced row form the solution set should be apparent just from looking at the matrix.
 
OK, I'm not really sure what the answer is.
One of my matrices is
1 2 0 0 -3 11
0 0 1 0 -5 15
0 0 0 1 -1 5

Could you point me in the right direction please.
 
Well that particular matrix will have an infinite number of solutions because you have more unknowns than equations. The matrix is already reduced as much as possible I believe. In this situation you would generally introduce one or more parameters and back substitute.

For example according to your matrix [tex]x_4=5+x_5[/tex] and [tex]x_3=15+5x_5[/tex] and [tex]x_1=11+3x_5-2x_2[/tex].

If you set [tex]x_5=t[/tex] and [tex]x_2=s[/tex] you should be able to solve for each variable in terms of s and t.
 
Last edited:
That was very helpful.
Thanks a million.
 
welcome :DD
 

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