Reduction of differntial equation

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Homework Help Overview

The discussion revolves around the reduction of a differential equation, specifically focusing on the transformation of the equation into the form x dv/dx = (v^2 + 1) / v. Participants express uncertainty about their algebraic manipulations and seek clarification on integration techniques.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss their attempts to simplify the equation and express confusion over potential mistakes in their algebra. Questions are raised about the validity of certain algebraic transformations and integration methods.

Discussion Status

The discussion is ongoing, with participants providing insights into their thought processes and questioning the correctness of their approaches. Some guidance on integration techniques has been offered, but no consensus has been reached regarding the algebraic manipulations.

Contextual Notes

Participants are grappling with the implications of their algebraic assumptions and the rules governing algebraic manipulation, indicating a need for clarity on these foundational concepts.

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Homework Statement



for this question, i 'm only able reduce it to become x dv/dx = (v^2 + 1) / v ... i have checked it several times, i just couldn't find my mistake...

Homework Equations





The Attempt at a Solution

 

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delsoo said:

Homework Statement



for this question, i 'm only able reduce it to become x dv/dx = (v^2 + 1) / v ... i have checked it several times, i just couldn't find my mistake...

Homework Equations



The Attempt at a Solution

What is [itex]\displaystyle \ \int\frac{v}{v^2+1}\,dv\ ?[/itex]
 
ln (V+1 ) as in my working
 
delsoo said:
ln (V+1 ) as in my working

$$\frac v {v^2+1} \ne \frac v {v(v+1)}$$
 
why can't i do in this way?
 
Because you can't make up your own algebra rules.$$
\frac v {v(v+1)}= \frac v {v^2+v} \ne \frac v {v^2+1}$$
 
SammyS said:
What is [itex]\displaystyle \ \int\frac{v}{v^2+1}\,dv\ ?[/itex]

delsoo said:
ln (V+1 ) as in my working
Take the derivative of ln (V+1 ) .

It's 1/(V+1) .


To do that integration, the substitution, u =(v2+1) works very nicely .
 

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