- #1

- 4

- 0

## Homework Statement

y'' +(y')^2 = 6(y') -9

## Homework Equations

u = y'

u' = y''

## The Attempt at a Solution

equation from 1 becomes

u' + U^2 = 6u - 9

du/dx + u ^2 = 6u-9

du/dx = -u^2 + 6u -9

du/dx = -(u^2 +6u - 9)

du/dx = -(u-3)^2

du/(u-3)^2 = - dx

integrate both sides

1/(u-3) = x

sub in dy/dx

1/(dy/dx -3) = x

from this point ive tried multiple ways to get dy and dx seperated but im not doing something right... thanks for the help