Is Reflection of an Incident Wave Lagging or Advancing?

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SUMMARY

The discussion centers on the phase change of a reflected wave, specifically addressing whether the reflection of an incident wave results in a lag or an advance in phase. It is established that the reflection of an incident wave introduces a phase shift of π radians. This phase shift can be interpreted as either an advance or a lag, as a phase difference of φ + π is mathematically equivalent to φ - π. Therefore, the distinction between lagging and advancing is irrelevant when considering the phase change due to reflection.

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Homework Statement
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Actually, maybe i am confusing something, or valuing unnecessary things, but this doubt arises and i am not sure how answer it.
The reflection of an incident wave changes (suppose it will change, we don't need to talk when or why to go on the discussion) by π rad, but, this reflection lags the wave or "advance" the phase?
That is, let's do a exercise:
Two waves are travelling:
ψ1 = a*sin(wt-kx)
ψ2 = a*sin(wt-kx+p)
THe difference of phase 2 to 1, clearly, is p.
If the wave two reflect with change of phase, the difference of phase between the waves will now be
p + π (advances) or p - π (lags)
?
 
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A phase difference of ##\phi+\pi## is equivalent to a phase difference of ##\phi-\pi##.

Show that ##\sin(\omega t + kx +\phi +\pi) = \sin(\omega t + kx +\phi - \pi)##.

So, there is no need to be concerned with whether the ##\pi## is an advance or a lag.

[If the wave reflects, ##\omega t - kx## changes to ##\omega t + kx##. If only the second wave reflects, then the two waves no longer differ by just a phase constant.]
 
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