Refractive Index and Angle of Refraction in Perspex Container Filled with Water

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The discussion revolves around calculating the angles of refraction for light passing through a perspex container filled with water. The initial angle of incidence is 70 degrees, and the refractive index of perspex is noted as 1.48, while that of water is 1.33. The user successfully determined that the angle of refraction in water is 26 degrees using Snell's Law. They are now seeking assistance to find the angles of refraction in the perspex and the air below the tank. The conversation highlights the challenge of transitioning from water to perspex, emphasizing the need to account for the air layer between them.
benhorris
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Light ray goes into a container at 70 degrees, the container is made of perspects. The refective index of perspex is 1.48.

What are the angles of refraction in (i) the water; (ii) the plastic, (iii) the air below the tank.

I can't work it out, the answer to the first bit is 26 degrees, i know that for sure, thanks...
 
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Please show us what you have done so far and where you are stuck.
 
ok using snells law, n (refractive index) = sin i / sin r, i have worked out the first one which equals

sin 20 / 1.33 = sin r (the refractive index is 1.33 for water)

= 26 degrees

next i need to find the refractive index of the perspects which is 1.48, done!
the hint for the question is " You need to work out the refractive index when light goes from water to plastic – just imagine a thin layer of air between them."

hum, i thought, i tryed all different ways of doing it without any joy, so I am stuck, confused and irritated.
 
Please note that the container is made of perspects, filled with water. The orginal ray of light came into the water at 70 degrees and i have worked out that the refraction of the light ray is 26 degrees. Just need to find the other two parts to the question...
 
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