Relate Magnetic Field, Rotations, and Length of Area in Spin 1/2 Systems?

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SUMMARY

The discussion focuses on the relationship between magnetic fields, rotations, and the length of area in spin 1/2 systems. The time evolution of the wavefunction is described using the equation |\psi(t)\rangle = \exp(\frac{-iHt}{\hbar})|\psi(0)\rangle, where H represents the Hamiltonian for a spin in a magnetic field. The connection between the Hamiltonian and the rotation generator is emphasized, indicating that understanding these concepts is crucial for solving time evolution problems in quantum mechanics.

PREREQUISITES
  • Quantum mechanics fundamentals
  • Understanding of spin 1/2 systems
  • Familiarity with Hamiltonians in quantum mechanics
  • Knowledge of wavefunction time evolution
NEXT STEPS
  • Study the Hamiltonian for a spin in a magnetic field
  • Learn about rotation generators in quantum mechanics
  • Explore the implications of the time evolution equation |\psi(t)\rangle = \exp(\frac{-iHt}{\hbar})|\psi(0)\rangle
  • Investigate the geometric interpretation of rotations in quantum systems
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Quantum physicists, students studying quantum mechanics, and researchers working on spin systems and magnetic field interactions.

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Here is the problem:
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How can relate the magnetic field and the rotations and then the length of the area? I only know that 2pi rotation give the initial state a pi phase but that's all.
where the hell I get the length from?

thanks
 
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This is just a time evolution problem. You know the initial wavevector will evolve in time according to:

[tex]|\psi(t)\rangle = \exp(\frac{-iHt}{\hbar})|\psi(0)\rangle[/tex]

Use the hamiltonian for a spin in a magnetic field. It will look very similar to the rotation generator. Also you know the time the particle is in the magnetic field knowing its velocity.
 

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