Related rates, baseball diamond

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SUMMARY

The discussion focuses on related rates in the context of a baseball diamond, which is a square with sides measuring 90 ft. A batter runs towards first base at a speed of 24 ft/s. When the batter is 45 ft from first base, the rate at which his distance from second base is decreasing is calculated to be approximately -34.0 ft/s. The setup for determining the rate of change of distance to third base follows a similar approach using the Pythagorean theorem.

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  • Understanding of related rates in calculus
  • Familiarity with the Pythagorean theorem
  • Knowledge of differentiation techniques
  • Basic concepts of motion and speed
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  • Learn how to differentiate functions with respect to time
  • Explore more complex scenarios involving multiple moving objects
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rocomath
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Even problem, very please!

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 24 ft/s.

a) At what rate is his distance from second base decreasing when he is halfway to the first base?

b) At what rate is his distance from third base increasing at the same moment?

Work for A:

Distance from each base is x, evaluate when x = 45 ft

The distance from the runner to 2nd base, is z

Using Pythagorean theorem:

2x^2=z^2

2x\frac{dx}{dt}=z\frac{dz}{dt}

2x\frac{dx}{dt}=x\sqrt 2\frac{dz}{dt}

\frac{dz}{dt}\approx -34.0 ft/s

I'm mainly concerned with the set up, same for B?
 
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rocomath said:
Even problem, very please!

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 24 ft/s.

a) At what rate is his distance from second base decreasing when he is halfway to the first base?

b) At what rate is his distance from third base increasing at the same moment?

Work for A:

Distance from each base is x, evaluate when x = 45 ft

The distance from the runner to 2nd base, is z

Using Pythagorean theorem:

2x^2=z^2

2x\frac{dx}{dt}=z\frac{dz}{dt}

2x\frac{dx}{dt}=x\sqrt 2\frac{dz}{dt}

\frac{dz}{dt}\approx -34.0 ft/s

I'm mainly concerned with the set up, same for B?

z = sqrt (90^2 + x^2)
z is your z
x is distance between him and first base

differentiate with respect to 't' .. don't know what you did

and same thing for the other base
 

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