1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Relating Image Distance and Image Height

  1. Sep 6, 2008 #1
    Regarding the thin lens equation,

    1/s + 1/s' = 1/f

    where s= distance of object from lens, s' = distance of image from lens, and f=focal length, can h and h' (h = height of object and h' = image height) be substituted from s and s'? I know the values are related through similar triangles, I am just not positive that they can be substituted in this equation. Could anyone shed some light on this being a valid substitution?
     
  2. jcsd
  3. Sep 6, 2008 #2

    Kurdt

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    You can't replace image distances with image heights in the thin lens equation but they are related by transverse magnification.

    [tex] M_T = \frac{y_i}{y_0} = -\frac{s_i}{s_0}[/tex]

    This occurs because in geometrical optics they both form sides of similar right triangles.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Relating Image Distance and Image Height
  1. Image Height (Replies: 2)

Loading...