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Relation between a photon's energy and momentum

  1. Feb 23, 2013 #1
    2wgzupd.jpg

    For part b), I can see that, as [itex]p = \frac{E}{c}[/itex], then a photon with twice the momentum must have twice the energy. However, I cannot see the answer to part a). My book states that [itex]k_2 = 4k_1[/itex], but I would have thought that, as per the answer to b), the KE is just twice that of the other, not four times?
     
  2. jcsd
  3. Feb 23, 2013 #2

    f95toli

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    The particle in part A is a proton, not a photon.
    And since it travelling at a speed much lower than c you can just use classical mechanics.
     
  4. Feb 23, 2013 #3
    Oh wow... All this reading about photons has me seeing the word everywhere -_-

    Thank you very much :)
     
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