Relationship between centripetal force and gravitational force of satelite

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SUMMARY

The centripetal force required for a satellite to maintain a stable orbit around the Earth must equal the gravitational force acting upon it. This relationship ensures that the centripetal acceleration, calculated using the formula v²/r, is provided solely by gravity. Any deviation in gravitational force would disrupt the circular path of the satellite, leading to instability in its orbit. Thus, for a stable circular orbit, gravitational acceleration must precisely match the centripetal acceleration.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula v²/r
  • Basic knowledge of gravitational force and its effects on objects in orbit
  • Familiarity with the concept of uniform circular motion
  • Awareness of satellite dynamics and orbital mechanics
NEXT STEPS
  • Study the derivation of the centripetal acceleration formula v²/r in detail
  • Explore gravitational force calculations for different celestial bodies
  • Learn about the effects of varying gravitational forces on satellite orbits
  • Investigate the role of thrusters in altering satellite trajectories
USEFUL FOR

Aerospace engineers, physics students, satellite operators, and anyone interested in orbital mechanics and satellite dynamics.

Tommy1995
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In order for a satelite to achieve an orbit around the Earth the centripetal force of it needs to be exactly the same as the force of gravitation which is acting upon the satelite. Why is this so?
 
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The question is slightly badly worded.

An acceleration occurs when there is a change of velocity. Velocity has components speed and direction and to change either component you need an acceleration. Centripetal acceleration is the name given to an acceleration that causes an object to move in a curved path.

In the case of a satelite gravity provids the centripetal acceleration. So gravity is allways "the same" as the centripetal acceleration (except perhaps when thrusters are being fired but let's ignore that).

So what I think you are really asking is this... What centripetal acceleration is required for a stable circular orbit and what happens if it's more or less than that value?

The centripetal acceleration required for uniform circular motion is given by v2/r. That equation is derived here..

http://www.gb.nrao.edu/~rmaddale/Education/Wvsta'98/Centripetal.html
or
http://dev.physicslab.org/Document....me=CircularMotion_CentripetalAcceleration.xml

So for a stable circular orbit gravity must provide exactly that acceleration. If it was more or less than that value the path wouldn't be circular.

Imagine you have got your satelite into a nice stable circular orbit, what happens if gravity were to suddenly increase dramatically or dissapear?
 
CWatters said:
Centripetal acceleration is the name given to an acceleration that causes an object to move in a curved path.

In the case of a satelite gravity provids the centripetal acceleration. So gravity is allways "the same" as the centripetal acceleration (except perhaps when thrusters are being fired but let's ignore that).

So for a stable circular orbit gravity must provide exactly that acceleration. If it was more or less than that value the path wouldn't be circular.

I can nicely see where your getting at CWatters! I was wondering if this might mean mean that the centripetal acceleration of a satelite traveling in its orbit would be the same as the gravitational acceleration provided by the planet it is orbiting?
 
Where else do you think it could come from? Gravity is the only force acting on the satellite, isn't it?
 
Thanks so much guys ! I finally understand this ! :d
 

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