Relationship between closing a switch and the total battery current

AI Thread Summary
Closing a switch creates an additional pathway for current to flow, which increases the total current in the circuit without altering the original path's current. The current through the capacitor (C) becomes an additional component when the switch is closed. Understanding the principles of series and parallel circuits is essential for grasping these concepts. The discussion emphasizes the importance of foundational knowledge in electrical circuits. Overall, the relationship between closing a switch and total battery current hinges on the configuration of the circuit.
kbrockway2021
Messages
1
Reaction score
0
Homework Statement
This problem solution says that by closing the switch, battery current will increase. However, the voltage is the same, and the resistance is only increasing by adding another light bulb. So how is the current increasing
Relevant Equations
V=IR
OQ.PNG
 
Physics news on Phys.org
Hello @kbrockway2021 ,
:welcome: ##\qquad## !​
See it this way: you add another path through which current can flow -- without changing anything in the original path, so here the current stays the same. When the swich is closed, the current through C will be additional.

##\ ##
 
You need to study the basics of serial and parallel
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Back
Top