Relationship between voltage, power and current

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SUMMARY

When voltage is doubled in a simple electric circuit with a fixed resistance, both current and power increase. Specifically, if the voltage across a resistor is increased from 10V to 20V, the current doubles from 1A to 2A, and the power dissipated quadruples from 10W to 40W. This relationship is governed by Ohm's Law and the power formula P = IV. Therefore, the correct answer to the question posed is that both current and power increase, confirming option D.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with electrical power calculations
  • Basic knowledge of circuit components (resistors, voltage sources)
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Study the implications of Ohm's Law in complex circuits
  • Learn about power factor and its impact on AC circuits
  • Explore the concept of energy loss in resistive circuits
  • Investigate the effects of varying resistance on current and power
USEFUL FOR

Electrical engineering students, educators, and anyone interested in understanding the fundamental relationships between voltage, current, and power in electrical circuits.

Imtiaz Ahmad
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Misplaced homework thread moved here by moderator, hence no template.
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b
 
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As usual: It depends. You have not specified the context. A drawing would help.
 
Svein said:
As usual: It depends. You have not specified the context. A drawing would help.
When we double the voltage in a simple electric circuit, we double the
A. Current
B. Power
C. Resistance
D. Both current and power
 
Imtiaz Ahmad said:
When we double the voltage in a simple electric circuit, we double the

you still haven't specified the circuit setup
until you fix (state) a couple of the variables, your Q cannot be answered

Dave
 
davenn said:
you still haven't specified the circuit setup
until you fix (state) a couple of the variables, your Q cannot be answered

Dave
Actually problem is that
This question is on the textbook which is recommended by government.
 
Imtiaz Ahmad said:
Actually problem is that
This question is on the textbook which is recommended by government.
So there is not show any circuit
 
Imtiaz Ahmad said:
So there is not show any circuit

so, so let me provide you with a circuit ...

upload_2017-1-23_18-22-49.png


a nice simple one, a battery and a resistor

do you know Ohm's Law ? ...
 
davenn said:
so, so let me provide you with a circuit ...

View attachment 111995

a nice simple one a battery and a resistor

do you know Ohm's Law ? ...
Yes I know
 
Imtiaz Ahmad said:
Yes I know

OK, good

so you have 10V across a 10 Ohm resistor ...
what is the current flowing in that circuit ?

show me your working :smile:
 
  • #10
davenn said:
OK, good

so you have 10V across a 10 Ohm resistor ...
what is the current flowing in that circuit ?

show me your working :smile:
1 A
 
  • #11
Imtiaz Ahmad said:
1 A

correct

so if you now increase the voltage to 20 V, what is the current in the circuit ?
 
  • #12
davenn said:
correct

so if you now increase the voltage to 20 V, what is the current in the circuit ?
2 A
 
  • #13
Imtiaz Ahmad said:
2 A

correct :smile:

so next, what is the formula for finding power ?
 
  • #14
davenn said:
correct [emoji2]
so next, what is the formula for finding power ?
P = I V
P= I (2) R
P = V (2) / R
 
  • #15
Imtiaz Ahmad said:
P = I V
P= I (2) R
P = V (2) / R

Yup
for ease we can use your first choice P = I x V

work out the two power levels for the examples we have just done

then answer your original Q ...

Imtiaz Ahmad said:
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b

Dave
 
  • #16
davenn said:
Yup
for ease we can use your first choice P = I x V

work out the two power levels for the examples we have just done

then answer your original Q ...
Dave
Mean D option is correct
 
  • #17
Imtiaz Ahmad said:
Mean D option is correct

yes, well done :smile:

wasn't too difficult to work out, huh :wink:
.

Dave
 
  • #18
davenn said:
yes, well done [emoji2]
wasn't too difficult to work out, huh :wink:
.

Dave
Thanks
But
Is this answer corrected. If current is double
P = 2 I * 2 V
 
  • #19
Imtiaz Ahmad said:
Is this answer corrected. If current is double

unlike voltage or resistance, current cannot just change
current is a RESULT of a given voltage across a given resistance
That is, current can ONLY change IF the voltage OR the resistance changes

And the power, in Watts, dissipated in a circuit, in our circuits above ( in the resistor)
is always related to the voltage across the resistance divided by the resistance

so for a fixed resistance, if the voltage is doubled, then the current is doubled and therefore so is the power dissipatedDave
 
  • #20
davenn said:
unlike voltage or resistance, current cannot just change
current is a RESULT of a given voltage across a given resistance
That is, current can ONLY change IF the voltage OR the resistance changes

And the power, in Watts, dissipated in a circuit, in our circuits above ( in the resistor)
is always related to the voltage across the resistance divided by the resistance

so for a fixed resistance, if the voltage is doubled, then the current is doubled and therefore so is the power dissipatedDave
Power dissipated mean?
 
  • #21
Mean energy loss
 
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  • #22
Imtiaz Ahmad said:
Power dissipated mean?

power lost, radiated, used up <---- take your pick, all the same :smile:
 
  • #23
davenn said:
power lost, radiated, used up <---- take your pick, all the same :smile:
[emoji3]
 
  • #24
I moved it to homework, where it better fits and can be found by others with similar questions.
 
  • #25
Imtiaz Ahmad said:
Mean D option is correct
Check again the amount by which current and power changed. They don't change by the same factor.
 
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  • #26
gneill said:
Check again the amount by which current and power changed. They don't change by the same factor.

I royally screwed up ... I blame old age and senility :wink: :rolleyes:

@imtiaz ... humble apologies answer b) current ... should have been answer

for power

10V x 1 A = 10 W

double the voltage, the current doubles as correctly stated but the power dissipated quadruples

20V x 2A = 40W

@gneill ... cheersDave
 
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  • #27
davenn said:
I royally screwed up ... I blame old age and senility :wink: :rolleyes:

@imtiaz ... humble apologies answer b) current ... should have been answer

for power

10V x 1 A = 10 W

double the voltage, the current doubles as correctly stated but the power dissipated quadruples

20V x 2A = 40W

@gneill ... cheersDave
So current is correct
 
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  • #28
Imtiaz Ahmad said:
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b
If circuit is simple
 
  • #29
Imtiaz Ahmad said:
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b
If circuit is double
 

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