Relationship between voltage, power and current

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Imtiaz Ahmad
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Misplaced homework thread moved here by moderator, hence no template.
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b
 
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Svein said:
As usual: It depends. You have not specified the context. A drawing would help.
When we double the voltage in a simple electric circuit, we double the
A. Current
B. Power
C. Resistance
D. Both current and power
 
Imtiaz Ahmad said:
When we double the voltage in a simple electric circuit, we double the

you still haven't specified the circuit setup
until you fix (state) a couple of the variables, your Q cannot be answered

Dave
 
davenn said:
you still haven't specified the circuit setup
until you fix (state) a couple of the variables, your Q cannot be answered

Dave
Actually problem is that
This question is on the textbook which is recommended by government.
 
Imtiaz Ahmad said:
Actually problem is that
This question is on the textbook which is recommended by government.
So there is not show any circuit
 
Imtiaz Ahmad said:
So there is not show any circuit

so, so let me provide you with a circuit ...

upload_2017-1-23_18-22-49.png


a nice simple one, a battery and a resistor

do you know Ohm's Law ? ...
 
davenn said:
so, so let me provide you with a circuit ...

View attachment 111995

a nice simple one a battery and a resistor

do you know Ohm's Law ? ...
Yes I know
 
Imtiaz Ahmad said:
Yes I know

OK, good

so you have 10V across a 10 Ohm resistor ...
what is the current flowing in that circuit ?

show me your working :smile:
 
davenn said:
OK, good

so you have 10V across a 10 Ohm resistor ...
what is the current flowing in that circuit ?

show me your working :smile:
1 A
 
Imtiaz Ahmad said:
1 A

correct

so if you now increase the voltage to 20 V, what is the current in the circuit ?
 
davenn said:
correct

so if you now increase the voltage to 20 V, what is the current in the circuit ?
2 A
 
davenn said:
correct [emoji2]
so next, what is the formula for finding power ?
P = I V
P= I (2) R
P = V (2) / R
 
Imtiaz Ahmad said:
P = I V
P= I (2) R
P = V (2) / R

Yup
for ease we can use your first choice P = I x V

work out the two power levels for the examples we have just done

then answer your original Q ...

Imtiaz Ahmad said:
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b

Dave
 
davenn said:
Yup
for ease we can use your first choice P = I x V

work out the two power levels for the examples we have just done

then answer your original Q ...
Dave
Mean D option is correct
 
Imtiaz Ahmad said:
Mean D option is correct

yes, well done :smile:

wasn't too difficult to work out, huh :wink:
.

Dave
 
davenn said:
yes, well done [emoji2]
wasn't too difficult to work out, huh :wink:
.

Dave
Thanks
But
Is this answer corrected. If current is double
P = 2 I * 2 V
 
Imtiaz Ahmad said:
Is this answer corrected. If current is double

unlike voltage or resistance, current cannot just change
current is a RESULT of a given voltage across a given resistance
That is, current can ONLY change IF the voltage OR the resistance changes

And the power, in Watts, dissipated in a circuit, in our circuits above ( in the resistor)
is always related to the voltage across the resistance divided by the resistance

so for a fixed resistance, if the voltage is doubled, then the current is doubled and therefore so is the power dissipatedDave
 
davenn said:
unlike voltage or resistance, current cannot just change
current is a RESULT of a given voltage across a given resistance
That is, current can ONLY change IF the voltage OR the resistance changes

And the power, in Watts, dissipated in a circuit, in our circuits above ( in the resistor)
is always related to the voltage across the resistance divided by the resistance

so for a fixed resistance, if the voltage is doubled, then the current is doubled and therefore so is the power dissipatedDave
Power dissipated mean?
 
Mean energy loss
 
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Imtiaz Ahmad said:
Power dissipated mean?

power lost, radiated, used up <---- take your pick, all the same :smile:
 
davenn said:
power lost, radiated, used up <---- take your pick, all the same :smile:
[emoji3]
 
Imtiaz Ahmad said:
Mean D option is correct
Check again the amount by which current and power changed. They don't change by the same factor.
 
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gneill said:
Check again the amount by which current and power changed. They don't change by the same factor.

I royally screwed up ... I blame old age and senility :wink: :rolleyes:

@imtiaz ... humble apologies answer b) current ... should have been answer

for power

10V x 1 A = 10 W

double the voltage, the current doubles as correctly stated but the power dissipated quadruples

20V x 2A = 40W

@gneill ... cheersDave
 
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davenn said:
I royally screwed up ... I blame old age and senility :wink: :rolleyes:

@imtiaz ... humble apologies answer b) current ... should have been answer

for power

10V x 1 A = 10 W

double the voltage, the current doubles as correctly stated but the power dissipated quadruples

20V x 2A = 40W

@gneill ... cheersDave
So current is correct
 
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Imtiaz Ahmad said:
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b
If circuit is simple
 
Imtiaz Ahmad said:
Hy,
If we double the voltage than what will be double
A. power
B. Current
C. Resistance
D. Both a & b
If circuit is double