##H^2(t)-8ρπG/3=-k/a^2(t)## (Lets suppose a(t)=1) then(adsbygoogle = window.adsbygoogle || []).push({});

##H^2(t)-8ρπG/3=-k## In equations ##k## can be -1,0,1.

Then If ##k<0## then ##-k>0## then

##H^2(t)-8ρπG/3>0 ##→Hyperbolic Universe. This means ##Ω_k>0## I mean If ##k## negative ##Ω_k## must be positive isnt it ? I am confused here.

In cosmology calculator says ##Ω_k=1-Ω_m-Ω_Λ##

(Its look like hyperbolic universe I am trying to understand)

ThanksΩ

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Relationship betwen ##Ω_k## and ##k##

**Physics Forums | Science Articles, Homework Help, Discussion**