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Simple Harmonic Motion with Impulse

  1. Feb 18, 2012 #1
    1. The problem statement, all variables and given/known data

    A particle P of mass 0.6kg is attached to one end of a light elastic spring of modulus of elasticity 72N and natural length 1.2m.
    The other end of the spring is fixed to a point A on the smooth horizontal table on which P rests. Initially P is at rest and is 1.2m from A.
    The particle receives an impulse of 3Ns in the direction AP.
    Given that t seconds after the impulse the displacement of P from its initial position is x metres.

    Find an equation for x in terms of t

    2. Relevant equations

    Tension in a spring, [itex]T = \frac{\lambda x}{l}[/itex]

    3. The attempt at a solution

    I know the answer will be in the form x=asin(ωt) and I am competent with finding the period etc but it is the impulse that is throwing me off.
     
  2. jcsd
  3. Feb 18, 2012 #2

    SammyS

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    The impulse will give the mass an (almost) instant momentum.
     
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