Relative Motion - Airplane Problem

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To solve the airplane velocity problem, the airplane's velocity is given as 325 km/h relative to the air, directed [S30W], while the wind velocity is 80 km/h [W]. The equation relating these velocities is aVg + pVa = pVg, where aVg is the wind velocity and pVa is the airplane's velocity relative to the air. There is confusion regarding the direction of pVa, with some interpreting it as [S] instead of [S30W]. A suggestion is made to break down the vectors into components to clarify the calculation and potentially resolve discrepancies in the expected answer.
harujina
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Homework Statement



An airplane has a velocity 325km/h relative to the air. It is going in a direction [S30W]. There is a wind velocity of 80km/h[W]. What is the velocity of the plane relative to the ground?

Homework Equations



aVg + pVa = pVg
(velocity of air relative to ground + velocity of plane relative to air = velocity of plane relative to ground)

The Attempt at a Solution



pVa = 325km/h and aVg = 80km/h [W] and pVg = ? [S30W]

correct?
i know pVg^2 = aVg^2 + pVa^2
but, I'm not getting the number I'm supposed to?
 
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The problem does not state specifically that the vectors form a 90 degree triangle. So you cannot assume that.
 
You could divide pVa into components.
 
Can you possibly attach a diagram showing the vectors?
 
harujina said:
pVa = 325km/h and aVg = 80km/h [W] and pVg = ? [S30W]
Where do you get the direction from? I read it as pVa = 325km/h [S30W] and the direction of pVg is unknown. See if that gives the desired answer.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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