1. The problem statement, all variables and given/known data Two ships A and B are 4 km apart. A is due west of B. If A moves with uniform velocity of 8 km/hr due east and B moves with a uniform velocity of 6 km/hr due south. Calculate 1) the magnitudeof the velocity of A in relation to B 2) the closest distance apart of A and B 2. Relevant equations The first solution is pretty simple but the second one, I dont get it. I know how to just solve it but without any intuition. Can someone help me get an intuitive idea of the solution of 2) ? The solution will be down there. 3. The attempt at a solution In the example BD is drawn from B to relative velocity of A with respect to B represented by AE. From the given distance between A and B is 4km i.e. AB = 4km. In ABE sin x = BE/AE = 6/10 ( x= Angle EAB, BE = Velocity of B in opposite direction, AE = relative velocity of A in respect to B ) x=36.67 Closest distance apart from A to B is BD. Now in BDA, BD = sin x * AB = sin 36.87 * 4 = 2.4 km This is the closest distance.